A radioactive element ²⁴²₉₂ X emits two α -particles, one electron and two positrons. The product nucleus is represented by ²³⁴P Y. The value of P is __________. Numerical answer type. Work it out, then open the answer.

Answer: 87. Two α: A = 242 - 8 = 234, Δ Z = -4. One electron ( β⁻): Δ Z = +1; two positrons ( β⁺): Δ Z = -2. P = 92 - 4 + 1 - 2 = 87 So P = 87.

A radioactive element ²⁴²₉₂ X emits two α -particles, one electron… | JEE Main 2023 (29 Jan, Shift 1)

Q12JEE Main 2023 · 29 JAN · SHIFT 1Easy

Radioactive Decays: Alpha, Beta, Gamma

A radioactive element ${}^{242}_{92}$ X emits two $\alpha$ -particles, one electron and two positrons. The product nucleus is represented by ${}^{234}_{\text{P}}$ Y. The value of P is __________.

Numerical answer type. Work it out, then open the answer.

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Answer: 87

Two $\alpha$ : $A = 242 - 8 = 234$ , $\Delta Z = -4$ .
One electron ( $\beta^-$ ): $\Delta Z = +1$ ; two positrons ( $\beta^+$ ): $\Delta Z = -2$ .
$P = 92 - 4 + 1 - 2 = 87$
So $P = 87$ .

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