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MHT CET 2025 (23 Apr, Shift 2) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from MHT CET 2025 (23 Apr, Shift 2)

Q3MHT CET 2025 · 23 APR · SHIFT 2Easy

Radioactive Decays: Alpha, Beta, Gamma

A radioactive element 92242X{}^{242}_{92}\text{X} emits two α\alpha particles, one electron and two positrons. The product nucleus is represented by P234Y{}^{234}_{P}\text{Y}. The value of PP is

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Answer: (a)

  1. Each α\alpha: A→A−4A \to A-4, Z→Z−2Z \to Z-2. Each electron (β−\beta^-): Z→Z+1Z \to Z+1. Each positron (β+\beta^+): Z→Z−1Z \to Z-1.
  2. Mass number: 242−2(4)=234242 - 2(4) = 234 (matches).
  3. Atomic number: P=92−2(2)+1−2=87P = 92 - 2(2) + 1 - 2 = 87
  4. So the answer is (a) 87.
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