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JEE Main 2010 (AIEEE) · Radioactive Decays: Alpha, Beta, Gamma

Radioactive Decays: Alpha, Beta, Gamma question from JEE Main 2010 (AIEEE)

Q28JEE Main 2010 · AIEEEMedium

Radioactive Decays: Alpha, Beta, Gamma

A radioactive nucleus (initial mass number $A$ and atomic number $Z$ emits $3\alpha$ - particles and $2$ positrons. The ratio of number of neutrons to that of protons in the final nucleus will be

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Answer: (b)

$3\alpha$ : $A' = A - 12$ , $\Delta Z = -6$ . $2\beta^+$ : $\Delta Z = -2$ .
Protons: $Z' = Z - 8$ .
Neutrons: $A' - Z' = A - 12 - (Z - 8) = A - Z - 4$ .
Ratio $= \dfrac{A-Z-4}{Z-8}$ , so the answer is (b).

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