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NEET 2014 (AIPMT) · Law of Radioactive Decay

Law of Radioactive Decay question from NEET 2014 (AIPMT)

Q93NEET 2014 · AIPMTEasy

Law of Radioactive Decay

A radioactive X with a half life 1.4 ×\times 109 years decays to Y which is stable. A sample of the rock from a cave was found to contain X and Y in the ratio 1: 7. The age of the rock is

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Answer: (c)

  1. Every decayed X atom becomes Y, so N0=NX+NYN_0 = N_X + N_Y.
  2. X:Y=1:7⇒NXN0=18=(12)3X:Y = 1:7 \Rightarrow \frac{N_X}{N_0} = \frac{1}{8} = \left(\frac{1}{2}\right)^3, i.e. 3 half-lives.
  3. Age =3×1.4×109=4.2×109= 3\times1.4\times10^9 = 4.2\times10^9 years.
  4. So the answer is (c) 4.20×1094.20\times10^9 years.
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