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JEE Main 2021 (25 Jul, Shift 1) · Total Internal Reflection

Total Internal Reflection question from JEE Main 2021 (25 Jul, Shift 1)

Q33JEE Main 2021 · 25 JUL · SHIFT 1Medium

Total Internal Reflection

A ray of laser of a wavelength 630 nm is incident at an angle of 30∘{}^\circ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1. Choose the correct option.

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Answer: (c)

  1. Critical angle for diamond-air: sin⁡C=12.42≈0.413⇒C≈24.4∘\sin C = \frac{1}{2.42} \approx 0.413 \Rightarrow C \approx 24.4^\circ.
  2. The angle of incidence 30∘>C30^\circ > C, so the light is totally internally reflected.
  3. (Snell's law would need sin⁡r=2.42×0.5=1.21>1\sin r = 2.42\times0.5 = 1.21 > 1, which is impossible.)
  4. So the answer is (c) refraction is not possible.
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