A ray of light is incident of the surface of a glass plate at an angle of incidence equal to Brewster's angle Φ. If μ denotes the refractive index of glass w.r.t. air, then what will be the angle between reflected and refracted rays? (a) 90° - sin ⁻¹(sin Φ/μ) (b) 90° (c) sin ⁻¹(μcos Φ) (d) 90° + Φ

Answer: (b). incidentreflectedrefractedΦΦr90°airglass At Brewster's angle, tan Φ = μ and Φ + r = 90°. Reflected ray makes Φ with the normal; refracted ray makes r on the other side. Angle between them = 180° - Φ - r = 180° - 90° = 90° So the answer is (b) 90°.

A ray of light is incident of the surface of a glass plate at an… | MHT CET 2026 (11 Apr, Shift 1)

Q2MHT CET 2026 · 11 APR · SHIFT 1Easy

Polarisation

A ray of light is incident of the surface of a glass plate at an angle of incidence equal to Brewster's angle $\Phi$ . If $\mu$ denotes the refractive index of glass w.r.t. air, then what will be the angle between reflected and refracted rays?

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Answer: (b)

At Brewster's angle, $\tan\Phi = \mu$ and $\Phi + r = 90^\circ$ .
Reflected ray makes $\Phi$ with the normal; refracted ray makes $r$ on the other side.
Angle between them $= 180^\circ - \Phi - r = 180^\circ - 90^\circ = 90^\circ$
So the answer is (b) $90^\circ$ .

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