A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to 60°. The refractive index of the prism material is √(2). The angle of incidence (in degrees) is__________ Numerical answer type. Work it out, then open the answer.

Answer: 45. At minimum deviation r = A/2 = 30°. sin i = μ sin r = √(2)×1/2 = 1/√(2) i = 45°, so the answer is 45.

A ray of light suffers minimum deviation when incident on a prism… | JEE Main 2025 (2 Apr, Shift 2)

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Prism, Dispersion & Scattering

A ray of light suffers minimum deviation when incident on a prism having angle of the prism equal to $60^\circ$ . The refractive index of the prism material is $\sqrt{2}$ . The angle of incidence (in degrees) is__________

Numerical answer type. Work it out, then open the answer.

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Answer: 45

At minimum deviation $r = \frac{A}{2} = 30^\circ$ .
$\sin i = \mu \sin r = \sqrt{2}\times\frac{1}{2} = \frac{1}{\sqrt{2}}$
$i = 45^\circ$ , so the answer is 45.

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