A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s. The maximum force exerted by spring on block is _________ N Numerical answer type. Work it out, then open the answer.

Answer: 20. ω = 2π/T = (2× 3.14)/(3.14) = 2 rad/s. Maximum force at the extreme: Fmax = mω² A. Fmax = 5× 4× 1 = 20 N. Answer: 20 N.

A rectangular block of mass 5 kg attached to a horizontal spiral… | JEE Main 2023 (10 Apr, Shift 2)

Q43JEE Main 2023 · 10 APR · SHIFT 2Medium

Velocity & Acceleration in SHM

A rectangular block of mass $5\text{ kg}$ attached to a horizontal spiral spring executes simple harmonic motion of amplitude $1\text{ m}$ and time period $3.14\text{ s}$ . The maximum force exerted by spring on block is _________ N

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 20

$\omega = \frac{2\pi}{T} = \frac{2\times 3.14}{3.14} = 2$ rad/s.
Maximum force at the extreme: $F_{max} = m\omega^2 A$ .
$F_{max} = 5\times 4\times 1 = 20$ N.
Answer: 20 N.

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