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MHT CET 2025 (21 Apr, Shift 1) · Thermal Radiation: Black Body, Stefan & Wien

Thermal Radiation: Black Body, Stefan & Wien question from MHT CET 2025 (21 Apr, Shift 1)

Q56MHT CET 2025 · 21 APR · SHIFT 1Medium

Thermal Radiation: Black Body, Stefan & Wien

A rectangular block of surface area A emits energy E per second at 27∘C27^\circ\text{C}. If length and breadth is reduced to half of initial value and temperature is raised to 327∘C327^\circ\text{C} then energy emitted per second becomes

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Answer: (b)

  1. E∝AT4E \propto A T^4.
  2. Length and breadth halved: A→A4A \to \frac{A}{4}.
  3. T:300 K→600 KT: 300\text{ K} \to 600\text{ K}, factor 1616.
  4. E′=164E=4EE' = \frac{16}{4}E = 4E, so the answer is (b).
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