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NEET 1992 (AIPMT) · Magnetic Flux & Faraday's Law

Magnetic Flux & Faraday's Law question from NEET 1992 (AIPMT)

Q87NEET 1992 · AIPMTEasy

Magnetic Flux & Faraday's Law

A rectangular coil of 20 turns and area of cross-section 25 sq. cm has a resistance of 100 Ω100\ \Omega. If a magnetic field which is perpendicular to the plane of coil changes at a rate of 1000 tesla per second, the current in the coil is

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Answer: (c)

  1. e=NAdBdte = NA\frac{dB}{dt}
  2. A=25A = 25 cm2=25×10−4^{2} = 25\times 10^{-4} m2^{2}: e=20×25×10−4×1000=50e = 20\times 25\times 10^{-4}\times 1000 = 50 V
  3. I=eR=50100=0.5I = \frac{e}{R} = \frac{50}{100} = 0.5 A
  4. So the answer is (c) 0.50.5 A.
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