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MHT CET 2025 (22 Apr, Shift 1) · Surface Energy & Work Done

Surface Energy & Work Done question from MHT CET 2025 (22 Apr, Shift 1)

Q12MHT CET 2025 · 22 APR · SHIFT 1Medium

Surface Energy & Work Done

A rectangular film of liquid is expanded from (5 cm×4 cm)(5\text{ cm} \times 4\text{ cm}) to (7 cm×8 cm)(7\text{ cm} \times 8\text{ cm}). If the work done is 3×10−4 J3 \times 10^{-4}\text{ J}, the surface tension of the liquid is (nearly)

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Answer: (b)

  1. Film has two surfaces: W=2TΔAW = 2T\Delta A.
  2. ΔA=56−20=36 cm2=36×10−4 m2\Delta A = 56 - 20 = 36\text{ cm}^2 = 36\times10^{-4}\text{ m}^2
  3. T=3×10−472×10−4≈0.042≈0.04 N/mT = \dfrac{3\times10^{-4}}{72\times10^{-4}} \approx 0.042 \approx 0.04\text{ N/m}
  4. So the answer is (b) 0.04 N/m0.04\text{ N/m}.
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