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MHT CET 2026 (12 May, Shift 1) · Surface Energy & Work Done

Surface Energy & Work Done question from MHT CET 2026 (12 May, Shift 1)

Q9MHT CET 2026 · 12 MAY · SHIFT 1Medium

Surface Energy & Work Done

A rectangular film of liquid is expanded from (66 cm ×5\times 5 cm) to (88 cm ×9\times 9 cm). If the work done is 4×10−44 \times 10^{-4} J, the surface tension of the liquid is

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Answer: (b)

  1. Film has two surfaces: W=2TΔAW = 2T\Delta A.
  2. ΔA=72−30=42 cm2=42×10−4 m2\Delta A = 72 - 30 = 42\text{ cm}^2 = 42\times10^{-4}\text{ m}^2
  3. T=4×10−42×42×10−4≈0.048≈0.05 N/mT = \dfrac{4\times10^{-4}}{2 \times 42\times10^{-4}} \approx 0.048 \approx 0.05\text{ N/m}
  4. So the answer is (b) 0.05 N/m0.05\text{ N/m}.
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