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NEET 2016 (Phase 2) · Surface Energy & Work Done

Surface Energy & Work Done question from NEET 2016 (Phase 2)

Q29NEET 2016 · PHASE 2Medium

Surface Energy & Work Done

A rectangular film of liquid is extended from (4 cm ×\times 2 cm) to (5 cm ×\times 4 cm). If the work done is 3 ×\times 10−-4 J, the value of the surface tension of the liquid is

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Answer: (b)

  1. Film has two surfaces: W=2TΔAW = 2T\Delta A.
  2. ΔA=20−8=12 cm2=12×10−4 m2\Delta A = 20 - 8 = 12\text{ cm}^2 = 12\times10^{-4}\text{ m}^2
  3. T=3×10−42×12×10−4=0.125 N m−1T = \dfrac{3\times10^{-4}}{2 \times 12\times10^{-4}} = 0.125\text{ N m}^{-1}
  4. So the answer is (b) 0.125 N m−10.125\text{ N m}^{-1}.
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