A rectangular loop of length 2.5 m and width 2 m is placed at 60° to a magnetic field of 4 T. The loop is removed from the field in 10 sec. The average emf induced in the loop during this time is (a) -2 V (b) +2 V (c) +1 V (d) -1 V

Answer: (c). Taking 60° as the angle between B and the normal: φ = BAcos 60°. φ = 4 × (2.5 × 2) × 1/2 = 10 Wb, and it falls to 0 when the loop is removed. e = -(Δφ)/(Δ t) = -(0 - 10)/(10) = +1 V So the answer is (c) +1 V.

A rectangular loop of length 2.5 m and width 2 m is placed at 60° to… | JEE Main 2024 (27 Jan, Shift 1)

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Magnetic Flux & Faraday's Law

A rectangular loop of length $2.5\text{ m}$ and width $2\text{ m}$ is placed at $60^\circ$ to a magnetic field of $4\text{ T}$ . The loop is removed from the field in $10\text{ sec}$ . The average emf induced in the loop during this time is

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Answer: (c)

Taking $60^\circ$ as the angle between $\vec{B}$ and the normal: $\phi = BA\cos 60^\circ$ .
$\phi = 4 \times (2.5 \times 2) \times \frac{1}{2} = 10$ Wb, and it falls to $0$ when the loop is removed.
$e = -\frac{\Delta\phi}{\Delta t} = -\frac{0 - 10}{10} = +1$ V
So the answer is (c) $+1$ V.

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