Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Motional EMF›Question 35

MHT CET 2021 (24 Sep, Shift 2) · Motional EMF

Motional EMF question from MHT CET 2021 (24 Sep, Shift 2)

Q35MHT CET 2021 · 24 SEP · SHIFT 2Easy

Motional EMF

A rectangular loop PQMNPQMN with movable arm PQPQ of length 12 cm12\text{ cm} and resistance 2 Ω2\ \Omega is placed in a uniform magnetic field of 0.1 T0.1\text{ T} acting perpendicular to the plane of the loop as shown in figure. The resistances of the arms MN, NP and MQ are negligible. The current induced in the loop when arm PQ is moved with velocity 20 ms−120\text{ ms}^{-1} is

Figure

Show answer and solution

Answer: (a)

  1. Emf in moving arm: ε=Blv=0.1×0.12×20=0.24\varepsilon = Blv = 0.1 \times 0.12 \times 20 = 0.24 V.
  2. Only PQ has resistance: I=εR=0.242I = \frac{\varepsilon}{R} = \frac{0.24}{2}.
  3. I=0.12I = 0.12 A. So the answer is (a).
Report a mistake

More questions on Motional EMF