A rectangular parallelopiped is measured as 1 cm × 1 cm × 100 cm. If its specific resistance is 3 × 10⁻⁷ Ω m, then the resistance between its two opposite rectangular faces will be ___________ × 10⁻⁷ Ω. Numerical answer type. Work it out, then open the answer.

Answer: 3. The rectangular faces are 1 cm × 100 cm; the distance between opposite rectangular faces is 1 cm. So l = 0.01 m and A = 0.01 × 1 = 0.01 m². R = (ρ l)/(A) = 3 × 10⁻⁷ × 0.010.01 = 3 × 10⁻⁷ Ω Answer: 3 (i.e. 3 × 10⁻⁷ Ω).

A rectangular parallelopiped is measured as 1 cm × 1 cm × 100 cm. If… | JEE Main 2023 (10 Apr, Shift 2)

Q14JEE Main 2023 · 10 APR · SHIFT 2Easy

Ohm's Law, Resistivity & Temperature

A rectangular parallelopiped is measured as $1\text{ cm} \times 1\text{ cm} \times 100\text{ cm}$ . If its specific resistance is $3 \times 10^{-7}\ \Omega\text{ m}$ , then the resistance between its two opposite rectangular faces will be ___________ $\times 10^{-7}\ \Omega$ .

Numerical answer type. Work it out, then open the answer.

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Answer: 3

The rectangular faces are $1\text{ cm} \times 100\text{ cm}$ ; the distance between opposite rectangular faces is $1\text{ cm}$ .
So $l = 0.01\text{ m}$ and $A = 0.01 \times 1 = 0.01\text{ m}^2$ .
$R = \dfrac{\rho l}{A} = \dfrac{3 \times 10^{-7} \times 0.01}{0.01} = 3 \times 10^{-7}\ \Omega$
Answer: $3$ (i.e. $3 \times 10^{-7}\ \Omega$ ).

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