A refrigerator consumes an average 35W power to operate between temperature -10° C to 25 ° C. If there is no loss of energy then how much average heat per second does it transfer? (a) 263 J/s (b) 298 J/s (c) 350 J/s (d) 35 J/s

Answer: (a). T₂ = 263 K, T₁ = 298 K, so β = (T₂)/(T₁ - T₂) = 263/35. Heat removed per second: Q₂ = β P = 263/35 × 35 = 263 J/s So the answer is (a) 263 J/s.

A refrigerator consumes an average 35W power to operate between… | JEE Main 2021 (26 Aug, Shift 2)

Q48JEE Main 2021 · 26 AUG · SHIFT 2Medium

Heat Engines, Refrigerators & Second Law

A refrigerator consumes an average 35W power to operate between temperature $-10^\circ$ C to 25 $^\circ$ C. If there is no loss of energy then how much average heat per second does it transfer?

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Answer: (a)

$T_2 = 263$ K, $T_1 = 298$ K, so $\beta = \frac{T_2}{T_1 - T_2} = \frac{263}{35}$ .
Heat removed per second: $Q_2 = \beta P = \frac{263}{35} \times 35 = 263$ J/s
So the answer is (a) 263 J/s.

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