Physics Circle home Student Login

Home›Chapters›Electrostatics PYQs›Electric Potential & Equipotentials›Question 38

MHT CET 2024 (3 May, Shift 2) · Electric Potential & Equipotentials

Electric Potential & Equipotentials question from MHT CET 2024 (3 May, Shift 2)

Q38MHT CET 2024 · 3 MAY · SHIFT 2Easy

Electric Potential & Equipotentials

A regular hexagon of side 10 cm has a charge 1 μC1\,\mu\text{C} at each of its vertices. The potential at the centre of hexagon is [14πε0=9×109\Bigg[\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9} SI unit ]\Bigg]

Show answer and solution

Answer: (c)

  1. Each vertex is one side length from the centre: r=0.1 mr = 0.1\text{ m}.
  2. V=6×9×109×10−60.1=6×9×104V = 6 \times \frac{9 \times 10^{9} \times 10^{-6}}{0.1} = 6 \times 9 \times 10^{4}
  3. V=5.4×105 VV = 5.4 \times 10^{5}\text{ V}
  4. So the answer is (c).
Report a mistake

More questions on Electric Potential & Equipotentials