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MHT CET 2025 (20 Apr, Shift 1) · RL and RC Series Circuits

RL and RC Series Circuits question from MHT CET 2025 (20 Apr, Shift 1)

Q15MHT CET 2025 · 20 APR · SHIFT 1Easy

RL and RC Series Circuits

A resistance of $200\ \Omega$ and an inductor of $\frac{1}{2\pi}\text{ H}$ are connected in series to a.c. voltage of 40 V and 100 Hz frequency. The phase angle between the voltage and current is

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Answer: (d)

$X_L = 2\pi f L = 2\pi \times 100 \times \frac{1}{2\pi} = 100\ \Omega$
$\tan\phi = \frac{X_L}{R} = \frac{100}{200} = 0.5$
So the answer is (d) $\tan^{-1}(0.5)$ .

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