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JEE Main 2022 (24 Jun, Shift 1) · AC Basics: Peak, RMS & Average Values

AC Basics: Peak, RMS & Average Values question from JEE Main 2022 (24 Jun, Shift 1)

Q27JEE Main 2022 · 24 JUN · SHIFT 1Medium

AC Basics: Peak, RMS & Average Values

A resistance of 40 Ω\Omega is connected to a source of alternating current rated 220 V, 50 Hz. Find the time taken by the current to change from its maximum value to the rms value:

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Answer: (a)

  1. Take I=I0cos⁡ωtI = I_0\cos\omega t; rms value when cos⁡ωt=12\cos\omega t = \frac{1}{\sqrt{2}}, i.e. ωt=π4\omega t = \frac{\pi}{4}.
  2. t=T8t = \frac{T}{8} with T=150T = \frac{1}{50} s =20= 20 ms
  3. t=2.5t = 2.5 ms (independent of RR)
  4. So the answer is (a) 2.5 ms.
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