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NEET 2015 (AIPMT, Cancelled Paper) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from NEET 2015 (AIPMT, Cancelled Paper)

Q69NEET 2015 · AIPMT · CANCELLED PAPERMedium

Power, Power Factor & Wattless Current

A resistance 'R' draws power 'P' when connected to an AC source. If an inductance is now placed in series with the resistance, such that the impedance of the circuit becomes 'Z'. the power drawn will be

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Answer: (c)

  1. With RR alone: P=V2RP = \frac{V^2}{R}.
  2. With LL added: P′=I2R=V2Z2RP' = I^2R = \frac{V^2}{Z^2}R.
  3. P′=V2R⋅R2Z2=P(RZ)2P' = \frac{V^2}{R} \cdot \frac{R^2}{Z^2} = P\left(\frac{R}{Z}\right)^2.
  4. So the answer is (c) P(RZ)2P\left(\frac{R}{Z}\right)^2.
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