A resistor is connected to a battery of 12 V emf and internal resistance 2 Ω. If the current in the circuit is 0.6 A, the terminal voltage of the battery is: (a) 10 V (b) 1.2 V (c) 12 V (d) 10.8 V

Answer: (d). Terminal voltage V = E - Ir V = 12 - 0.6 × 2 = 12 - 1.2 = 10.8 V So the answer is (d) 10.8 V.

A resistor is connected to a battery of 12 V emf and internal… | NEET 2026

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Cells: EMF, Internal Resistance & Combinations

A resistor is connected to a battery of 12 V emf and internal resistance $2\ \Omega$ . If the current in the circuit is 0.6 A, the terminal voltage of the battery is:

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Answer: (d)

Terminal voltage $V = E - Ir$
$V = 12 - 0.6 \times 2 = 12 - 1.2 = 10.8\text{ V}$
So the answer is (d) 10.8 V.

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