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JEE Main 2021 (24 Feb, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from JEE Main 2021 (24 Feb, Shift 1)

Q90JEE Main 2021 · 24 FEB · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

A resonance circuit having inductance and resistance 2 $\times$ 10 $-$ 4 H and 6.28 $\Omega$ respectively oscillates at 10 MHz frequency. The value of quality factor of this resonator is ___________. [ $\pi$ = 3.14]

Numerical answer type. Work it out, then open the answer.

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Answer: 2000

$Q = \frac{\omega L}{R} = \frac{2\pi f L}{R}$
$Q = \frac{2\times3.14\times10^{7}\times2\times10^{-4}}{6.28} = \frac{6.28\times2000}{6.28}$
$Q = 2000$

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