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JEE Main 2021 (24 Feb, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from JEE Main 2021 (24 Feb, Shift 1)

Q90JEE Main 2021 · 24 FEB · SHIFT 1Easy

Resonance, Bandwidth & Q Factor

A resonance circuit having inductance and resistance 2 ×\times 10−-4 H and 6.28Ω\Omega respectively oscillates at 10 MHz frequency. The value of quality factor of this resonator is ___________. [π\pi = 3.14]

Numerical answer type. Work it out, then open the answer.

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Answer: 2000

  1. Q=ωLR=2πfLRQ = \frac{\omega L}{R} = \frac{2\pi f L}{R}
  2. Q=2×3.14×107×2×10−46.28=6.28×20006.28Q = \frac{2\times3.14\times10^{7}\times2\times10^{-4}}{6.28} = \frac{6.28\times2000}{6.28}
  3. Q=2000Q = 2000
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