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MHT CET 2026 (20 Apr, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2026 (20 Apr, Shift 1)

Q30MHT CET 2026 · 20 APR · SHIFT 1Medium

Thermodynamic Processes

A rigid diatomic gas $\left(\gamma = \frac{7}{5}\right)$ is compressed adiabatically to volume $\left(\frac{V_i}{32}\right)$ , where $V_i$ is the initial volume. The initial temperature of the gas is ' $T_i$ ' K and the final temperature is ' $xT_i$ ' K. The value of $x$ is

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Answer: (c)

$T_f = T_i\left(\frac{V_i}{V_f}\right)^{\gamma - 1} = T_i(32)^{2/5}$
$32^{2/5} = (2^5)^{2/5} = 2^2 = 4$
So the answer is (c) $x = 4$ .

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