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JEE Main 2019 (10 Jan, Shift 2) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from JEE Main 2019 (10 Jan, Shift 2)

Q56JEE Main 2019 · 10 JAN · SHIFT 2Medium

Rotational Kinematics & Dynamics

A rigid massless rod of length 3l has two masses attached at each end as shown in the figure. The rod is pivoted at point P on the horizontal axis (see figure). When released from initial horizontal position, its instantaneous angular acceleration will be -

Figure

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Answer: (a)

5M₀g2M₀gPl2lnet τ = M₀gl
  1. Torques about P: 5M05M_0 at ll on one side, 2M02M_0 at 2l2l on the other.
  2. Net τ=5M0gl−2M0g(2l)=M0gl\tau = 5M_0gl - 2M_0g(2l) = M_0gl
  3. I=5M0l2+2M0(2l)2=13M0l2I = 5M_0l^2 + 2M_0(2l)^2 = 13M_0l^2
  4. α=τI=g13l\alpha = \frac{\tau}{I} = \frac{g}{13l}
  5. So the answer is (a) g13l\frac{g}{13l}.
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