A ring is placed at the bottom of a trough containing four immiscible liquids of refractive indices 1.0, 2.0, 3.0 and 4.0 poured one above the other of heights 10 cm, 20 cm, 30 cm, and 40 cm respectively. The apparent depth at which the ring appears, when seen from outside is __________ cm. Numerical answer type. Work it out, then open the answer.

Answer: 40. Apparent depth = Σ (ti)/(μi). d = 10/1 + 20/2 + 30/3 + 40/4 = 10 + 10 + 10 + 10 So the ring appears at a depth of 40 cm.

A ring is placed at the bottom of a trough containing four immiscible… | JEE Main 2022 (30 Jul, Shift 2)

Q51JEE Main 2022 · 30 JUL · SHIFT 2Medium

Refraction, Glass Slab & Apparent Depth

A ring is placed at the bottom of a trough containing four immiscible liquids of refractive indices $1.0, 2.0, 3.0$ and $4.0$ poured one above the other of heights $10\text{ cm}, 20\text{ cm}, 30\text{ cm}$ , and $40\text{ cm}$ respectively. The apparent depth at which the ring appears, when seen from outside is __________ cm.

Numerical answer type. Work it out, then open the answer.

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Answer: 40

Apparent depth $= \sum \frac{t_i}{\mu_i}$ .
$d = \frac{10}{1} + \frac{20}{2} + \frac{30}{3} + \frac{40}{4} = 10 + 10 + 10 + 10$
So the ring appears at a depth of $40\text{ cm}$ .

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Refraction, Glass Slab & Apparent Depth question from JEE Main 2022 (30 Jul, Shift 2)

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