Physics Circle home Student Login

Home›Chapters›Laws of Motion PYQs›Friction on an Incline›Question 25

JEE Main 2016 (9 Apr, Shift 1) · Friction on an Incline

Friction on an Incline question from JEE Main 2016 (9 Apr, Shift 1)

Q25JEE Main 2016 · 9 APR · SHIFT 1Medium

Friction on an Incline

A rocket is fired vertically from the earth with an acceleration of 2g, where g is the gravitational acceleration. On an inclined plane inside the rocket, making an angle θ\theta with the horizontal, a point object of mass m is kept. The minimum coefficient of friction μ\mumin between the mass and the inclined surface such that the mass does not move is:

Show answer and solution

Answer: (a)

  1. In the rocket frame, effective gravity geff=g+2g=3gg_{eff} = g + 2g = 3g (pseudo force acts downward).
  2. No slipping: mgeffsin⁡θ≤μmgeffcos⁡θm g_{eff}\sin\theta \le \mu m g_{eff}\cos\theta; geffg_{eff} cancels.
  3. So the answer is (a) μmin=tan⁡θ\mu_{min} = \tan\theta.
Report a mistake

More questions on Friction on an Incline