A rocket with a lift-off mass 3.5 × 10⁴ kg is blasted upwards with an initial acceleration of 10 m/s² Then the initial thrust of the blast is (a) 3.5 × 10⁵ N (b) 7.0 × 10⁵ N (c) 14.0 × 10⁵ N (d) 1.75 × 10⁵ N

Answer: (b). At lift-off: F - mg = ma ⇒ F = m(g + a). F = 3.5 × 10⁴ × (10 + 10) = 7.0 × 10⁵ N (taking g = 10 m/s²) So the answer is (b) 7.0 × 10⁵ N.

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Impulse & Momentum Conservation

A rocket with a lift-off mass $3.5 \times 10^{4}\text{ kg}$ is blasted upwards with an initial acceleration of $10\text{ m/s}^{2}$ Then the initial thrust of the blast is

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Answer: (b)

At lift-off: $F - mg = ma \Rightarrow F = m(g + a)$ .
$F = 3.5 \times 10^{4} \times (10 + 10) = 7.0 \times 10^{5}\text{ N}$ (taking $g = 10\text{ m/s}^2$ )
So the answer is (b) $7.0 \times 10^{5}$ N.

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