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JEE Main 2025 (7 Apr, Shift 1) · Composite & Cut-Out Bodies

Composite & Cut-Out Bodies question from JEE Main 2025 (7 Apr, Shift 1)

Q3JEE Main 2025 · 7 APR · SHIFT 1Medium

Composite & Cut-Out Bodies

A rod of length 5 L is bent right angle keeping one side length as 2 L.

The position of the centre of mass of the system:

(Consider $L = 10\text{ cm}$ )

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Answer: (a)

Mass $\propto$ length: vertical part $3L$ with CM at $(0, 1.5L)$ ; horizontal part $2L$ with CM at $(L, 0)$ .
$x_{cm} = \frac{2L \cdot L}{5L} = 0.4L = 4$ cm
$y_{cm} = \frac{3L \cdot 1.5L}{5L} = 0.9L = 9$ cm
So the answer is (a) $4\hat{i} + 9\hat{j}$ .

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