A rod of length 60 cm rotates with a uniform angular velocity 20 rad… | JEE Main 2024 (4 Apr, Shift 2)

Q13JEE Main 2024 · 4 APR · SHIFT 2Medium

Rotating Conductors & AC Generator

A rod of length $60\text{ cm}$ rotates with a uniform angular velocity $20\text{ rad s}^{-1}$ about its perpendicular bisector, in a uniform magnetic field $0.5\text{ T}$ . The direction of magnetic field is parallel to the axis of rotation. The potential difference between the two ends of the rod is _________ V.

Numerical answer type. Work it out, then open the answer.

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Answer: 0

Rotating about the perpendicular bisector, each half is a rod of length $\frac{l}{2}$ rotating about the centre.
Each end is at the same potential difference $\frac{1}{2}B\omega\left(\frac{l}{2}\right)^2$ from the centre, in the same sense.
So both ends are at the same potential: $V_1 - V_2 = 0\text{ V}$ .

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