Physics Circle home Student Login

Home›Chapters›Electromagnetic Induction PYQs›Rotating Conductors & AC Generator›Question 10

MHT CET 2024 (3 May, Shift 2) · Rotating Conductors & AC Generator

Rotating Conductors & AC Generator question from MHT CET 2024 (3 May, Shift 2)

Q10MHT CET 2024 · 3 MAY · SHIFT 2Easy

Rotating Conductors & AC Generator

A rod of length ' ll ' is rotated with angular velocity ' ω\omega ' about its one end, perpendicular to a magnetic field of induction ' BB '. The e.m.f. induced in the rod is

Show answer and solution

Answer: (b)

  1. A point at distance xx moves with v=ωxv = \omega x; de=Bωx dxde = B\omega x\,dx.
  2. e=∫0lBωx dx=12Bl2ωe = \int_0^l B\omega x\,dx = \tfrac{1}{2}Bl^2\omega
  3. So the answer is (b) 0.5 Bl2ω0.5\,Bl^2\omega.
Report a mistake

More questions on Rotating Conductors & AC Generator