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MHT CET 2020 (19 Oct, Shift 2) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from MHT CET 2020 (19 Oct, Shift 2)

Q46MHT CET 2020 · 19 OCT · SHIFT 2Easy

Rotational Kinematics & Dynamics

A rope is wound around a solid cylinder of mass 1 kg and radius 0.4 m. What is the angular acceleration of cylinder, if the rope is pulled with a force of 25 N? (Cylinder is rotating about its own axis.)

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Answer: (a)

  1. Solid cylinder: I=12MR2=12×1×0.42=0.08I = \frac{1}{2}MR^2 = \frac{1}{2} \times 1 \times 0.4^2 = 0.08 kg m2^2
  2. τ=FR=25×0.4=10\tau = FR = 25 \times 0.4 = 10 N m
  3. α=τI=100.08=125\alpha = \frac{\tau}{I} = \frac{10}{0.08} = 125 rad/s2^2
  4. So the answer is (a) 125 rad/s2^2.
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