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MHT CET 2024 (4 May, Shift 1) · Rotational Kinetic Energy, Work & Power

Rotational Kinetic Energy, Work & Power question from MHT CET 2024 (4 May, Shift 1)

Q22MHT CET 2024 · 4 MAY · SHIFT 1Medium

Rotational Kinetic Energy, Work & Power

A rotating body has angular momentum ' LL '. If its frequency is doubled and kinetic energy is halved, its angular momentum will be

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Answer: (a)

  1. L=2KωL = \frac{2K}{\omega}
  2. ω′=2ω\omega' = 2\omega, K′=K2K' = \frac{K}{2}: L′=2(K/2)2ω=L4L' = \frac{2(K/2)}{2\omega} = \frac{L}{4}
  3. So the answer is (a) L4\frac{L}{4}.
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