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JEE Main 2022 (24 Jun, Shift 2) · Law of Radioactive Decay

Law of Radioactive Decay question from JEE Main 2022 (24 Jun, Shift 2)

Q51JEE Main 2022 · 24 JUN · SHIFT 2Medium

Law of Radioactive Decay

A sample contains 10−-2 kg each of two substances A and B with half lives 4 s and 8 s respectively. The ratio of their atomic weights is 1: 2. The ratio of the amounts of A and B after 16 s is x100\frac{x}{100}. The value of x is ___________.

Numerical answer type. Work it out, then open the answer.

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Answer: 25

  1. In 16 s: A goes through 16/4=416/4 = 4 half-lives, B through 16/8=216/8 = 2.
  2. Mass of A left =10−2/16= 10^{-2}/16 kg; mass of B left =10−2/4= 10^{-2}/4 kg.
  3. Ratio of amounts (mass) =1/161/4=14=25100= \frac{1/16}{1/4} = \frac{1}{4} = \frac{25}{100}.
  4. So x=25x = 25.
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