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JEE Main 2024 (6 Apr, Shift 1) · Molecular Speeds & Maxwell Distribution

Molecular Speeds & Maxwell Distribution question from JEE Main 2024 (6 Apr, Shift 1)

Q24JEE Main 2024 · 6 APR · SHIFT 1Easy

Molecular Speeds & Maxwell Distribution

A sample contains mixture of helium and oxygen gas. The ratio of root mean square speed of helium and oxygen in the sample, is:

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Answer: (c)

  1. At the same temperature vrms∝1Mv_{rms} \propto \frac{1}{\sqrt{M}}.
  2. MHe=4M_{He} = 4, MO2=32M_{O_2} = 32
  3. vHevO2=324=8=22\frac{v_{He}}{v_{O_2}} = \sqrt{\frac{32}{4}} = \sqrt{8} = 2\sqrt{2}
  4. So the answer is (c) 221\frac{2\sqrt{2}}{1}.
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