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MHT CET 2023 (10 May, Shift 1) · Thermodynamic Processes

Thermodynamic Processes question from MHT CET 2023 (10 May, Shift 1)

Q151MHT CET 2023 · 10 MAY · SHIFT 1Medium

Thermodynamic Processes

A sample of gas at temperature TT is adiabatically expanded to double its volume. The work done by the gas in the process is (CPCV=γ=32) (R=\left(\frac{C_P}{C_V} = \gamma = \frac{3}{2}\right)\ (R = gas constant ))

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Answer: (d)

  1. Adiabatic: TVγ−1=constTV^{\gamma-1} = \text{const}, so T2=T⋅2−1/2=T2T_2 = T \cdot 2^{-1/2} = \frac{T}{\sqrt{2}}.
  2. Work by gas (taking 1 mole): W=R(T−T/2)1/2=2RT(1−12)W = \frac{R(T - T/\sqrt{2})}{1/2} = 2RT\left(1 - \frac{1}{\sqrt{2}}\right)
  3. W=RT(2−2)W = RT(2 - \sqrt{2})
  4. So the answer is (d) RT(2−2)RT(2 - \sqrt{2}).
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