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JEE Main 2021 (31 Aug, Shift 2) · Thermodynamic Processes

Thermodynamic Processes question from JEE Main 2021 (31 Aug, Shift 2)

Q192JEE Main 2021 · 31 AUG · SHIFT 2Medium

Thermodynamic Processes

A sample of gas with γ\gamma = 1.5 is taken through an adiabatic process in which the volume is compressed from 1200 cm3 to 300 cm3. If the initial pressure is 200 kPa. The absolute value of the workdone by the gas in the process = _____________ J.

Numerical answer type. Work it out, then open the answer.

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Answer: 480

  1. P2=P1(V1V2)γ=200×41.5=1600P_2 = P_1\left(\frac{V_1}{V_2}\right)^{\gamma} = 200 \times 4^{1.5} = 1600 kPa
  2. ∣W∣=P2V2−P1V1γ−1|W| = \frac{P_2V_2 - P_1V_1}{\gamma - 1}
  3. P2V2=1600×103×300×10−6=480P_2V_2 = 1600\times10^3 \times 300\times10^{-6} = 480 J, P1V1=200×103×1200×10−6=240P_1V_1 = 200\times10^3 \times 1200\times10^{-6} = 240 J
  4. ∣W∣=480−2400.5=480|W| = \frac{480 - 240}{0.5} = 480 J
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