Physics Circle home Student Login

Home›Chapters›Gravitation PYQs›Satellites - Orbital Velocity & Period›Question 13

JEE Main 2025 (24 Jan, Shift 1) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2025 (24 Jan, Shift 1)

Q13JEE Main 2025 · 24 JAN · SHIFT 1Medium

Satellites - Orbital Velocity & Period

A satellite is launched into a circular orbit of radius ' R ' around the earth. A second satellite is launched into an orbit of radius 1.03 R. The time period of revolution of the second satellite is larger than the first one approximately by

Show answer and solution

Answer: (c)

  1. T∝r3/2T \propto r^{3/2}, so T2T1=(1.03)3/2\frac{T_2}{T_1} = (1.03)^{3/2}.
  2. (1.03)3/2≈1+32(0.03)=1.045(1.03)^{3/2} \approx 1 + \frac{3}{2}(0.03) = 1.045
  3. So T2T_2 is larger by about 4.5%4.5\%, answer (c).
Report a mistake

More questions on Satellites - Orbital Velocity & Period