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JEE Main 2024 (9 Apr, Shift 2) · Satellite Energy & Weightlessness

Satellite Energy & Weightlessness question from JEE Main 2024 (9 Apr, Shift 2)

Q12JEE Main 2024 · 9 APR · SHIFT 2Medium

Satellite Energy & Weightlessness

A satellite of 103 kg10^{3}\text{ kg} mass is revolving in circular orbit of radius 2R2R. If 104R6 J\frac{10^{4}R}{6}\text{ J} energy is supplied to the satellite, it would revolve in a new circular orbit of radius

(use g=10 m/s2,R=g = 10\text{ m/s}^{2}, R = radius of earth)

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Answer: (b)

  1. With GM=gR2GM = gR^2: E=−GMm2r=−mgR22rE = -\frac{GMm}{2r} = -\frac{mgR^2}{2r}.
  2. Initial (r=2Rr = 2R): Ei=−mgR4E_i = -\frac{mgR}{4}. Energy given 104R6=mgR6\frac{10^4R}{6} = \frac{mgR}{6} (since mg=104mg = 10^4 N).
  3. Ef=−mgR4+mgR6=−mgR12E_f = -\frac{mgR}{4} + \frac{mgR}{6} = -\frac{mgR}{12}.
  4. −mgR22r=−mgR12⇒r=6R-\frac{mgR^2}{2r} = -\frac{mgR}{12} \Rightarrow r = 6R.
  5. So the answer is (b) 6R6R.
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