A satellite of mass ' m ' is revolving around the earth of mass ' M ' in an orbit of radius ' r ' with constant angular velocity ' ω '. The angular momentum of satellite is ( G = Universal constant of gravitation) (a) m(GMr)3/2 (b) m(GMr) (c) m(GMr)1/2 (d) m(GMr)-1/2

Answer: (c). L = mvr with orbital speed v = √(GM/r). L = mr√(GM/r) = m√(GMr) So the answer is (c) m(GMr)1/2.

A satellite of mass ' m ' is revolving around the earth of mass ' M '… | MHT CET 2024 (15 May, Shift 1)

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Satellites - Orbital Velocity & Period

A satellite of mass ' $m$ ' is revolving around the earth of mass ' $M$ ' in an orbit of radius ' $r$ ' with constant angular velocity ' $\omega$ '. The angular momentum of satellite is ( $G =$ Universal constant of gravitation)

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Answer: (c)

$L = mvr$ with orbital speed $v = \sqrt{\frac{GM}{r}}$ .
$L = mr\sqrt{\frac{GM}{r}} = m\sqrt{GMr}$
So the answer is (c) $m(GMr)^{1/2}$ .

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