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JEE Main 2024 (5 Apr, Shift 2) · Satellites - Orbital Velocity & Period

Satellites - Orbital Velocity & Period question from JEE Main 2024 (5 Apr, Shift 2)

Q24JEE Main 2024 · 5 APR · SHIFT 2Medium

Satellites - Orbital Velocity & Period

A satellite revolving around a planet in stationary orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius of orbit of the satellite is:

(Given == Radius of geo-stationary orbit for earth is 4.2×104 km4.2 \times 10^{4}\text{ km})

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Answer: (d)

  1. T2=4π2r3GM⇒r3∝MT2T^2 = \frac{4\pi^2 r^3}{GM} \Rightarrow r^3 \propto MT^2
  2. r3re3=MpMe(TpTe)2=14×(624)2=164\frac{r^3}{r_e^3} = \frac{M_p}{M_e}\left(\frac{T_p}{T_e}\right)^2 = \frac{1}{4}\times\left(\frac{6}{24}\right)^2 = \frac{1}{64}
  3. r=re4=4.2×1044=1.05×104r = \frac{r_e}{4} = \frac{4.2\times10^4}{4} = 1.05\times10^4 km
  4. So the answer is (d).
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