Student Login

Home›Chapters›Motion in One Dimension PYQs›Equations of Kinematics›Question 23

JEE Main 2021 (26 Feb, Shift 2) · Equations of Kinematics

Equations of Kinematics question from JEE Main 2021 (26 Feb, Shift 2)

Q23JEE Main 2021 · 26 FEB · SHIFT 2Easy

Equations of Kinematics

A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of $\frac{t_1}{t_2}$ will be:

Show answer and solution

Answer: (c)

Peak speed reached after accelerating: $v = a_1t_1$
Retarding to rest: $0 = v - a_2t_2 \Rightarrow v = a_2t_2$
$a_1t_1 = a_2t_2 \Rightarrow \frac{t_1}{t_2} = \frac{a_2}{a_1}$ . So the answer is (c).

Report a mistake

More questions on Equations of Kinematics

An engine of a train, moving with uniform acceleration, passes the signal-post with…JEE Main 2021 (25 Feb, Shift 1)
Two bodies ' A ' and ' B ' start from the same point at the same instant and move along a…MHT CET 2021 (20 Sep, Shift 1)
A car accelerates from rest at a constant rate α for some time after which it decelerates…JEE Main 2021 (17 Mar, Shift 1)
A driver applies the brakes on seeing the red traffic signal 400 m ahead. At the time of…MHT CET 2021 (22 Sep, Shift 2)
A small block slides down on a smooth inclined plane, starting from rest at time t = 0…NEET 2021
A moving body is covering distances which are proportional to square of the time. Then…MHT CET 2020 (16 Oct, Shift 1)
A particle moves from the point (2.0i + 4.0j) m, at t = 0, with an initial velocity (5.0i…JEE Main 2019 (11 Jan, Shift 2)
In a car race on straight road, car A takes a time t less than car B at the finish and…JEE Main 2019 (9 Jan, Shift 2)