A screw gauge has 50 divisions on its circular scale. The circular… | JEE Main 2020 (6 Sep, Shift 1)

Q51JEE Main 2020 · 6 SEP · SHIFT 1Medium

Least Count, Vernier Callipers & Screw Gauge

A screw gauge has 50 divisions on its circular scale. The circular scale is 4 units ahead of the pitch scale marking, prior to use. Upon one complete rotation of the circular scale, a displacement of 0.5mm is noticed on the pitch scale. The nature of zero error involved and the least count of the screw gauge, are respectively:

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Answer: (c)

Circular scale zero is ahead (below the line) before use, so the zero error is positive.
LC $= \dfrac{0.5\text{ mm}}{50} = 0.01\text{ mm} = 10\ \mu\text{m}$
So the answer is (c) Positive, $10\ \mu$ m.

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