A series combination of resistor of resistance 100 Ω, inductor of inductance 1 H and capacitor of capacitance 6.25 is connected to an ac source. The quality factor of the circuit will be __________ Numerical answer type. Work it out, then open the answer.

Answer: 4. Q = 1/R√(L/C) √16.25×10⁻⁶ = 12.5×10⁻³ = 400 Q = (400)/(100) = 4 So the quality factor is 4.

A series combination of resistor of resistance 100 Ω, inductor of… | JEE Main 2023 (8 Apr, Shift 2)

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Resonance, Bandwidth & Q Factor

A series combination of resistor of resistance $100\ \Omega$ , inductor of inductance $1\text{ H}$ and capacitor of capacitance $6.25\ \mu\text{F}$ is connected to an ac source. The quality factor of the circuit will be __________

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 4

$Q = \frac{1}{R}\sqrt{\frac{L}{C}}$
$\sqrt{\frac{1}{6.25\times10^{-6}}} = \frac{1}{2.5\times10^{-3}} = 400$
$Q = \frac{400}{100} = 4$
So the quality factor is 4.

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