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MHT CET 2024 (15 May, Shift 1) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from MHT CET 2024 (15 May, Shift 1)

Q50MHT CET 2024 · 15 MAY · SHIFT 1Medium

Resonance, Bandwidth & Q Factor

A series $L - C - R$ circuit containing a resistance ' $R$ ' has angular frequency ' $\omega$ '. At resonance the voltage across resistance and inductor are ' $V_R$ ' and ' $V_L$ ' respectively, then value of capacitance will be

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Answer: (a)

$I = \frac{V_R}{R}$ ; at resonance $X_L = X_C = \frac{1}{\omega C}$ .
$V_L = IX_C = \frac{V_R}{R\omega C}$
$C = \frac{V_R}{V_L\omega R}$
So the answer is (a).

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