A series LCR circuit is subjected to an ac signal of 200 V, 50 Hz. If the voltage across the inductor (L = 10 mH) is 31.4 V, then the current in this circuit is _______. (a) 10 A (b) 10 mA (c) 68 A (d) 63 A

Answer: (a). XL = 2π f L = 2π × 50 × 10 × 10⁻³ = 3.14 Ω I = (VL)/(XL) = (31.4)/(3.14) = 10 A So the answer is (a) 10 A.

A series LCR circuit is subjected to an ac signal of 200 V, 50 Hz. If… | JEE Main 2024 (5 Apr, Shift 2)

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Series LCR Circuit

A series LCR circuit is subjected to an ac signal of $200\text{ V},\ 50\text{ Hz}$ . If the voltage across the inductor $(L = 10\text{ mH})$ is $31.4\text{ V}$ , then the current in this circuit is _______.

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Answer: (a)

$X_L = 2\pi f L = 2\pi \times 50 \times 10 \times 10^{-3} = 3.14\ \Omega$
$I = \frac{V_L}{X_L} = \frac{31.4}{3.14} = 10$ A
So the answer is (a) 10 A.

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