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MHT CET 2026 (19 Apr, Shift 1) · Beats

Beats question from MHT CET 2026 (19 Apr, Shift 1)

Q6MHT CET 2026 · 19 APR · SHIFT 1Easy

Beats

A set of 1414 tuning forks is arranged in a series of increasing frequencies. Each fork produces 'xx' beats per second with the preceding fork and the last fork is an octave of the first fork. If the seventh fork has the frequency of 114114 Hz, the value of xx is

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Answer: (c)

  1. Last (14th) fork =f+13x=2f⇒f=13x= f + 13x = 2f \Rightarrow f = 13x
  2. 7th fork =f+6x=19x=114⇒x=6= f + 6x = 19x = 114 \Rightarrow x = 6
  3. So the answer is (c) 66.
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