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MHT CET 2024 (4 May, Shift 2) · Beats

Beats question from MHT CET 2024 (4 May, Shift 2)

Q33MHT CET 2024 · 4 MAY · SHIFT 2Easy

Beats

A set of 28 turning forks is arranged in an increasing order of frequencies. Each fork produces ' $x$ ' beats per second with the preceding fork and the last fork is an octave of the first. If the frequency of the $12$ th fork is 152 Hz, the value of ' $x$ ' (no. of beats per second) is

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Answer: (b)

Last (28th) fork $= f + 27x = 2f \Rightarrow f = 27x$
12th fork $= f + 11x = 38x = 152 \Rightarrow x = 4$
So the answer is (b) 4.

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