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MHT CET 2026 (19 May, Shift 2) · Beats

Beats question from MHT CET 2026 (19 May, Shift 2)

Q5MHT CET 2026 · 19 MAY · SHIFT 2Easy

Beats

A set of 88 tuning forks is arranged in ascending order of frequencies. Each fork produces 44 beats with the next one and frequency of last fork is octave of first. The frequency of 55th fork is

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Answer: (c)

  1. Fork frequencies: f,f+4,…f, f+4, \dots; last (8th) =f+7×4=f+28= f + 7 \times 4 = f + 28
  2. Octave: f+28=2f⇒f=28 Hzf + 28 = 2f \Rightarrow f = 28\text{ Hz}
  3. 5th fork =28+4×4=44 Hz= 28 + 4 \times 4 = 44\text{ Hz}
  4. So the answer is (c) 4444 Hz.
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